1. **State the problem:** We need to find the intercepts of the line given by the equation $$-4x + 2y = 16$$ to help graph it. 2. **Recall the intercepts:** - The x-intercept is where the line crosses the x-axis, so $y=0$. - The y-intercept is where the line crosses the y-axis, so $x=0$. 3. **Find the x-intercept:** Set $y=0$ in the equation: $$-4x + 2(0) = 16$$ $$-4x = 16$$ Divide both sides by $-4$: $$\cancel{-4}x / \cancel{-4} = 16 / -4$$ $$x = -4$$ So the x-intercept is at $(-4, 0)$. 4. **Find the y-intercept:** Set $x=0$ in the equation: $$-4(0) + 2y = 16$$ $$2y = 16$$ Divide both sides by $2$: $$\cancel{2}y / \cancel{2} = 16 / 2$$ $$y = 8$$ So the y-intercept is at $(0, 8)$. 5. **Summary:** The line crosses the x-axis at $(-4, 0)$ and the y-axis at $(0, 8)$. Plotting these points and drawing a line through them will graph the equation. **Final answer:** - x-intercept: $(-4, 0)$ - y-intercept: $(0, 8)$