1. **State the problem:** We need to find the intercepts of the line given by the equation $$3x + 5y = -15$$ to help graph it. 2. **Recall the intercepts:** - The **x-intercept** is where the line crosses the x-axis, so $y=0$. - The **y-intercept** is where the line crosses the y-axis, so $x=0$. 3. **Find the x-intercept:** Set $y=0$ in the equation: $$3x + 5(0) = -15$$ $$3x = -15$$ Divide both sides by 3: $$\cancel{3}x = \cancel{3}\times -5$$ $$x = -5$$ So the x-intercept is at $(-5, 0)$. 4. **Find the y-intercept:** Set $x=0$ in the equation: $$3(0) + 5y = -15$$ $$5y = -15$$ Divide both sides by 5: $$\cancel{5}y = \cancel{5}\times -3$$ $$y = -3$$ So the y-intercept is at $(0, -3)$. 5. **Summary:** The line crosses the x-axis at $(-5, 0)$ and the y-axis at $(0, -3)$. Plot these points and draw a straight line through them to graph the equation. **Final answer:** - x-intercept: $(-5, 0)$ - y-intercept: $(0, -3)$