1. **State the problem:** Find the x-intercept and y-intercept of the line given by the equation $$y=\frac{2}{3}x - 2$$ and graph the line. 2. **Y-intercept:** The y-intercept occurs when $$x=0$$. Substitute $$x=0$$ into the equation: $$y=\frac{2}{3}(0) - 2 = -2$$ So, the y-intercept is at the point $$(0, -2)$$. 3. **X-intercept:** The x-intercept occurs when $$y=0$$. Set $$y=0$$ and solve for $$x$$: $$0 = \frac{2}{3}x - 2$$ Add 2 to both sides: $$2 = \frac{2}{3}x$$ Multiply both sides by $$\frac{3}{2}$$ to isolate $$x$$: $$x = 2 \times \frac{3}{2} = 3$$ So, the x-intercept is at the point $$(3, 0)$$. 4. **Summary:** - Y-intercept: $$(0, -2)$$ - X-intercept: $$(3, 0)$$ 5. **Graphing:** The line passes through these two points and has slope $$\frac{2}{3}$$, meaning it rises 2 units for every 3 units it moves to the right. This completes the solution.