Subjects algebra

Intercepts Linear

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1. **State the problem:** Find the x-intercept and y-intercept of the linear equation $$8x - 9y = 144$$. 2. **Recall the intercept rules:** - The x-intercept occurs where $$y=0$$. - The y-intercept occurs where $$x=0$$. 3. **Find the x-intercept:** Set $$y=0$$ in the equation: $$8x - 9(0) = 144 \implies 8x = 144$$ Divide both sides by 8: $$x = \frac{144}{8} = 18$$ So, the x-intercept is $$(18, 0)$$. 4. **Find the y-intercept:** Set $$x=0$$ in the equation: $$8(0) - 9y = 144 \implies -9y = 144$$ Divide both sides by -9: $$y = \frac{144}{-9} = -16$$ So, the y-intercept is $$(0, -16)$$. **Final answer:** - x-intercept: $$(18, 0)$$ - y-intercept: $$(0, -16)$$