1. **State the problem:** Find the intersection point of the system of equations: $$\begin{cases} 2x + y = 8 \\ 2x + 4y = 20 \end{cases}$$ 2. **Multiply the first equation by 1 and the second equation by 1 (already done):** $$2x + y = 8$$ $$2x + 4y = 20$$ 3. **Subtract the first equation from the second to eliminate $x$: ** $$ (2x + 4y) - (2x + y) = 20 - 8 $$ $$ 2x + 4y - 2x - y = 12 $$ $$ 3y = 12 $$ 4. **Solve for $y$: ** $$ y = \frac{12}{3} = 4 $$ 5. **Substitute $y=4$ into the first equation to find $x$: ** $$ 2x + 4 = 8 $$ $$ 2x = 8 - 4 = 4 $$ $$ x = \frac{4}{2} = 2 $$ 6. **Final answer:** The intersection point is $$ (x, y) = (2, 4) $$ This means the two lines cross at the point where $x=2$ and $y=4$.