1. **Stating the problem:** Find the points of intersection between the two functions $$f_1(x) = x^2 - 4$$ and $$f_2(x) = x + 2$$. 2. **Formula and approach:** To find intersection points, set $$f_1(x) = f_2(x)$$ and solve for $$x$$: $$x^2 - 4 = x + 2$$ 3. **Rearrange the equation:** Move all terms to one side: $$x^2 - x - 6 = 0$$ 4. **Factor the quadratic:** $$x^2 - x - 6 = (x - 3)(x + 2) = 0$$ 5. **Solve for $$x$$:** $$x - 3 = 0 \Rightarrow x = 3$$ $$x + 2 = 0 \Rightarrow x = -2$$ 6. **Find corresponding $$y$$ values:** For $$x=3$$: $$y = f_2(3) = 3 + 2 = 5$$ For $$x=-2$$: $$y = f_2(-2) = -2 + 2 = 0$$ 7. **Final answer:** The graphs intersect at points $$\boxed{(3, 5)}$$ and $$\boxed{(-2, 0)}$$.