1. Problem statement: We are asked to find the value of $f^{-1}(3)$, which means we want to find the input $x$ such that $f(x) = 3$. 2. Important rule: The inverse function $f^{-1}(y)$ gives the $x$-value for which the function $f(x)$ equals $y$. So $f^{-1}(3)$ is the $x$ such that $f(x) = 3$. 3. From the graph, observe the function $f$ and find the point where the output (y-value) is 3. 4. Since the graph is defined on the interval $[-3;6]$ and the y-axis on the graph only goes up to about 2, the function $f$ does not reach the value 3 in the given interval. 5. Therefore, $f^{-1}(3)$ does not exist because there is no $x$ in $[-3;6]$ such that $f(x) = 3$. Final answer: $$f^{-1}(3) \text{ does not exist in the interval } [-3;6].$$