1. **Problem statement:** Find the inverse function of $ق(s) = 3s + 2$. 2. **Formula and rules:** To find the inverse function $ق^{-1}(y)$, swap $s$ and $y$ and solve for $s$. 3. **Work:** Start with $y = 3s + 2$. Swap variables: $s = 3y + 2$. Solve for $y$: $$s = 3y + 2$$ $$3y = s - 2$$ $$y = \frac{s - 2}{3}$$ 4. **Answer:** The inverse function is $$ق^{-1}(s) = \frac{s - 2}{3}$$ This means for any output $s$ of the original function, the inverse function returns the input that produced it.