1. The problem states that the function $f(x)$ is invertible and asks to find $f^{-1}(-3)$. 2. By definition, the inverse function $f^{-1}(y)$ gives the value of $x$ such that $f(x) = y$. 3. We want to find $x$ such that $f(x) = -3$. 4. From the graph description, the curve crosses near the point $(0, -3)$, meaning $f(0) = -3$. 5. Therefore, $f^{-1}(-3) = 0$ because the inverse function returns the $x$ value corresponding to $y = -3$. Final answer: $$f^{-1}(-3) = 0$$