1. The problem asks to find the graph of the inverse function $y = f^{-1}(x)$ given the graph of $y = f(x)$. 2. The inverse function $f^{-1}$ swaps the roles of $x$ and $y$, so the graph of $f^{-1}$ is the reflection of the graph of $f$ across the line $y = x$. 3. The given graph has vertices at approximately $(-1,-2)$, $(1,-1)$, $(2,2)$, and $(3,3)$. 4. To find the vertices of $f^{-1}$, swap each vertex coordinate: - $(-1,-2)$ becomes $(-2,-1)$ - $(1,-1)$ becomes $(-1,1)$ - $(2,2)$ becomes $(2,2)$ (this point lies on $y=x$ so it remains the same) - $(3,3)$ becomes $(3,3)$ (also on $y=x$) 5. Plotting these points and connecting them piecewise linearly will give the graph of $y = f^{-1}(x)$. 6. The key rule is that the inverse graph is the reflection of the original graph about the line $y=x$. Final answer: The graph of $y = f^{-1}(x)$ has vertices at $(-2,-1)$, $(-1,1)$, $(2,2)$, and $(3,3)$ connected piecewise linearly.