1. **State the problem:** We are given that $y$ is inversely proportional to the square of $(x+3)$, i.e., $y \propto \frac{1}{(x+3)^2}$. When $x=2$, $y=5$. We need to find the formula for $y$ in terms of $x$. 2. **Write the formula for inverse proportionality:** $$y = \frac{k}{(x+3)^2}$$ where $k$ is the constant of proportionality. 3. **Use the given values to find $k$:** Substitute $x=2$ and $y=5$: $$5 = \frac{k}{(2+3)^2} = \frac{k}{5^2} = \frac{k}{25}$$ Multiply both sides by 25: $$5 \times 25 = k$$ $$k = 125$$ 4. **Write the final formula for $y$:** $$y = \frac{125}{(x+3)^2}$$ **Answer:** $$\boxed{y = \frac{125}{(x+3)^2}}$$