1. **State the problem:** We are given that $y$ is inversely proportional to the square root of $x$, i.e., $y \propto \frac{1}{\sqrt{x}}$. When $x=25$, $y=4.4$. We need to find $y$ when $x=49$ to 2 decimal places. 2. **Write the formula:** Since $y$ is inversely proportional to $\sqrt{x}$, we can write: $$y = \frac{k}{\sqrt{x}}$$ where $k$ is the constant of proportionality. 3. **Find the constant $k$:** Substitute $x=25$ and $y=4.4$: $$4.4 = \frac{k}{\sqrt{25}} = \frac{k}{5}$$ Multiply both sides by 5: $$k = 4.4 \times 5 = 22$$ 4. **Find $y$ when $x=49$:** Substitute $k=22$ and $x=49$ into the formula: $$y = \frac{22}{\sqrt{49}} = \frac{22}{7} = 3.142857...$$ 5. **Round the answer:** To 2 decimal places, $y = 3.14$. **Final answer:** $y = 3.14$ when $x=49$.