1. **State the problem:**
If $x$ varies inversely as $y$, and $x=4$ when $y=8$, find $x$ when $y=1$.
2. **Formula and explanation:**
Inverse variation means:
$$x \times y = k$$
where $k$ is a constant.
3. **Find the constant $k$ using given values:**
$$4 \times 8 = k$$
$$k = 32$$
4. **Use $k$ to find $x$ when $y=1$:**
$$x \times 1 = 32$$
$$x = 32$$
5. **Final answer:**
When $y=1$, $x=32$.
Inverse Variation 731E7B
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