1. **State the problem:** Olive invested some money at 6% per year and three times that amount at 8% per year. The total annual return from both investments is 2400. 2. **Define variables:** Let the amount invested at 6% be $x$. Then the amount invested at 8% is $3x$. 3. **Write the equation for total return:** The return from the first investment is $0.06x$. The return from the second investment is $0.08 \times 3x = 0.24x$. The total return is given as 2400, so: $$0.06x + 0.24x = 2400$$ 4. **Simplify the equation:** $$0.30x = 2400$$ 5. **Solve for $x$:** $$x = \frac{2400}{0.30}$$ $$x = 8000$$ 6. **Find the amount invested at each rate:** Amount at 6% = $8000$ Amount at 8% = $3 \times 8000 = 24000$ **Final answer:** Olive invested 8000 at 6% and 24000 at 8%.