1. The problem is to isolate $y$ in the expression $\frac{2y}{5} + 16$. 2. To isolate $y$, we want to get $y$ alone on one side of the equation. 3. First, subtract 16 from both sides: $$\frac{2y}{5} + 16 - 16 = 0 - 16$$ which simplifies to $$\frac{2y}{5} = -16$$ 4. Next, to get rid of the fraction, multiply both sides by 5: $$5 \times \frac{2y}{5} = 5 \times (-16)$$ 5. This cancels the 5 in the denominator: $$\cancel{5} \times \frac{2y}{\cancel{5}} = -80$$ so $$2y = -80$$ 6. Finally, divide both sides by 2 to solve for $y$: $$\frac{2y}{2} = \frac{-80}{2}$$ 7. Cancel the 2 on the left: $$\cancel{2} y / \cancel{2} = -40$$ so $$y = -40$$ Answer: $y = -40$