Subjects algebra

Jades Journey

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1. Let's first understand Jade's journey and the distances at given times. 2. She travels from home to the gym in 20 minutes at a constant speed, so at 20 minutes she is at the gym, which is 6 km from home. 3. She stays at the gym for 40 minutes, so from 20 minutes to 60 minutes she remains at 6 km. 4. Then she travels back home in 30 minutes, so from 60 minutes to 90 minutes, the distance decreases from 6 km to 0 km. 5. Now, let's check each point: - A at (20 min, 6 km): This is where she arrives at the gym, so point A lies on the graph. - B at (60 min, 6 km): At 60 minutes, she is still at the gym before leaving, so point B lies on the graph. - C at (80 min, 6 km): Between 60 and 90 minutes she is traveling home, so distance cannot be 6 km at 80 min, thus C is not on the graph. - D at (20 min, 3 km): At 20 min she is at the gym at 6 km, not 3 km, so D is not on the graph. - E at (60 min, 3 km): At 60 min she is at the gym at 6 km, so E not on the graph. - F at (80 min, 3 km): At 80 min, traveling back home, she would be halfway between 6 and 0 km around 3 km. Calculate distance at 80 min: Traveling time back is 30 min, speed = 6 km / 30 min = 0.2 km/min. From 60 to 80 min is 20 minutes, so distance traveled home = 0.2 \times 20 = 4 km. Distance from home at 80 min = 6 - 4 = 2 km, so F at 3 km is slightly off, so not exactly on the graph. - G at (50 min, 0 km): At 50 min she is still at the gym (6 km), so 0 km at 50 min is incorrect. - H at (90 min, 0 km): At 90 min she just arrives home, so point H is on the graph. Final points on the graph: A, B, and H.