1. **Problem Statement:** The total cost $C$ to build a wooden fence varies jointly with the length $L$ of the fence and the square root of the wood quality index $Q$. Given a 10-meter fence with wood quality index 9 costs 1200, find the cost for a 15-meter fence with wood quality index 4.
2. **Write the joint variation equation:** Since $C$ varies jointly with $L$ and $\sqrt{Q}$, the formula is:
$$C = k L \sqrt{Q}$$
where $k$ is the constant of proportionality.
3. **Find the constant $k$:** Substitute the known values $C=1200$, $L=10$, and $Q=9$:
$$1200 = k \times 10 \times \sqrt{9}$$
$$1200 = k \times 10 \times 3$$
$$1200 = 30k$$
Solve for $k$:
$$k = \frac{1200}{30} = 40$$
4. **Write the equation with $k$:**
$$C = 40 L \sqrt{Q}$$
5. **Find the cost for $L=15$ and $Q=4$:**
$$C = 40 \times 15 \times \sqrt{4}$$
$$C = 40 \times 15 \times 2$$
$$C = 40 \times 30 = 1200$$
**Final answer:** The total cost to build the 15-meter fence with wood quality index 4 is $1200$.
This shows how joint variation works: the cost depends on both length and the square root of quality, and we find the constant from given data before calculating the unknown cost.
Joint Variation Cost
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.