1. **State the problem:** A kangaroo chases a rabbit that starts 150 feet ahead. Each time the kangaroo leaps 12 feet, the rabbit leaps 7 feet simultaneously. We want to find how many leaps the kangaroo must make to catch the rabbit. 2. **Set up the equation:** Let $n$ be the number of leaps the kangaroo makes. The kangaroo's distance after $n$ leaps is $12n$ feet. 3. The rabbit starts 150 feet ahead and moves $7n$ feet after $n$ leaps, so its position is $150 + 7n$ feet. 4. The kangaroo catches the rabbit when their positions are equal: $$12n = 150 + 7n$$ 5. **Solve for $n$:** $$12n - 7n = 150$$ $$\cancel{12}n - \cancel{7}n = 150$$ $$5n = 150$$ 6. Divide both sides by 5: $$\frac{5n}{\cancel{5}} = \frac{150}{\cancel{5}}$$ $$n = 30$$ 7. **Answer:** The kangaroo must make **30 leaps** to catch the rabbit.