1. **Problem statement:** Mr. Jamil has $10^{2/7}$ acres of cultivable land. He cultivates rice on $\frac{3}{6}$ of his land. He cultivates wheat and jute on $\frac{5}{14} \times \frac{3}{10}$ of the rest of his land. We need to find: a) The acreage used for rice cultivation. b) The total part of the land used for wheat and jute. c) Which crop type was cultivated mostly. 2. **Step 1: Calculate the land used for rice.** Rice land = $\frac{3}{6} \times 10^{2/7}$ acres. 3. **Step 2: Calculate the rest of the land after rice cultivation.** Rest land = Total land - Rice land = $10^{2/7} - \frac{3}{6} \times 10^{2/7} = 10^{2/7} \times \left(1 - \frac{3}{6}\right) = 10^{2/7} \times \frac{3}{6}$. 4. **Step 3: Calculate the land used for wheat and jute.** Wheat and jute land = $\frac{5}{14} \times \frac{3}{10} \times$ Rest land = $\frac{5}{14} \times \frac{3}{10} \times 10^{2/7} \times \frac{3}{6}$. 5. **Step 4: Calculate the total part of the land used for wheat and jute.** Total part = $\frac{5}{14} \times \frac{3}{10} \times \frac{3}{6} = \frac{5 \times 3 \times 3}{14 \times 10 \times 6} = \frac{45}{840} = \frac{3}{56}$. 6. **Step 5: Compare the land used for rice and wheat+jute.** Rice part = $\frac{3}{6} = \frac{1}{2} = 0.5$. Wheat and jute part = $\frac{3}{56} \approx 0.0536$. Since $0.5 > 0.0536$, rice was cultivated mostly. **Final answers:** a) Land used for rice = $\frac{3}{6} \times 10^{2/7}$ acres. b) Total part used for wheat and jute = $\frac{3}{56}$ of the land. c) Rice was cultivated mostly.