1. **Problem statement:** Mr. Jamil has $10^{2/7}$ acres of cultivable land. He cultivates rice on $\frac{3}{6}$ of his land and wheat and jute on $\frac{5}{14} \times \frac{3}{10}$ of the rest of his land. 2. **Step 1: Calculate the land used for rice cultivation.** - Total land = $10^{2/7}$ acres. - Rice land = $\frac{3}{6}$ of total land. - Rice land = $\frac{3}{6} \times 10^{2/7}$ acres. 3. **Step 2: Calculate the rest of the land after rice cultivation.** - Rest land = Total land - Rice land = $10^{2/7} - \frac{3}{6} \times 10^{2/7} = \left(1 - \frac{3}{6}\right) \times 10^{2/7} = \frac{3}{6} \times 10^{2/7}$ acres. 4. **Step 3: Calculate the land used for wheat and jute cultivation.** - Wheat and jute land = $\frac{5}{14} \times \frac{3}{10}$ of the rest land. - Wheat and jute land = $\frac{5}{14} \times \frac{3}{10} \times \frac{3}{6} \times 10^{2/7}$ acres. 5. **Step 4: Calculate the total part of land used for wheat and jute cultivation.** - Total part = $\frac{5}{14} \times \frac{3}{10} \times \frac{3}{6} = \frac{5 \times 3 \times 3}{14 \times 10 \times 6} = \frac{45}{840} = \frac{3}{56}$. 6. **Step 5: Compare the land used for rice and wheat & jute to find which crop is cultivated mostly.** - Rice land part = $\frac{3}{6} = \frac{1}{2} = 0.5$. - Wheat and jute land part = $\frac{3}{56} \approx 0.0536$. - Since $0.5 > 0.0536$, rice is cultivated mostly. **Final answers:** - a) Land used for rice cultivation = $\frac{3}{6} \times 10^{2/7}$ acres. - b) Part of land used for wheat and jute = $\frac{3}{56}$. - c) Rice is cultivated mostly because $\frac{1}{2} > \frac{3}{56}$.