1. **State the problem:** We have two shops selling the same laptop. Shop A sells it for 475 with a 16% discount. Shop B sells it with a 15% discount, and the total price after discount is 408. We need to find which shop offers more savings. 2. **Formulas and rules:** - Discount amount = Original price \times Discount rate - Sale price = Original price - Discount amount 3. **Calculate Shop A's discount and sale price:** - Discount for Shop A = $475 \times 0.16 = 76$ - Sale price for Shop A = $475 - 76 = 399$ 4. **Calculate Shop B's original price:** - Let original price for Shop B be $x$ - After 15% discount, price is $408$ - So, $x - 0.15x = 408$ which simplifies to $0.85x = 408$ - Solve for $x$: $$x = \frac{408}{0.85} = 480$$ 5. **Calculate Shop B's discount:** - Discount for Shop B = $480 \times 0.15 = 72$ 6. **Compare savings:** - Shop A saves $76$ - Shop B saves $72$ **Conclusion:** Shop A saves more money by $4$.