1. **State the problem:** We want to find the largest whole number $x$ such that $8 + x$ is larger than $2x$. 2. **Write the inequality:** $$8 + x > 2x$$ 3. **Solve the inequality:** Subtract $x$ from both sides: $$8 + \cancel{x} > 2x - \cancel{x}$$ $$8 > x$$ 4. **Interpret the result:** This means $x$ must be less than 8. 5. **Find the largest whole number satisfying this:** The largest whole number less than 8 is 7. 6. **Verify with the table:** For $x=7$: $$8 + 7 = 15$$ $$2 \times 7 = 14$$ Since $15 > 14$, $x=7$ works. For $x=8$: $$8 + 8 = 16$$ $$2 \times 8 = 16$$ Since $16$ is not greater than $16$, $x=8$ does not satisfy the inequality. **Final answer:** The largest whole number $x$ so that $8 + x$ is larger than $2x$ is **7**.