1. **State the problem:** A homeowner wants to resod a front lawn that measures 10 \frac{1}{2} yards long and 6 \frac{2}{3} yards wide. The landscaper charges 8 per square yard for labor and materials. We need to find the total cost. 2. **Convert mixed numbers to improper fractions:** - Length: 10 \frac{1}{2} = \frac{21}{2} - Width: 6 \frac{2}{3} = \frac{20}{3} 3. **Calculate the area of the lawn:** $$\text{Area} = \text{Length} \times \text{Width} = \frac{21}{2} \times \frac{20}{3}$$ 4. **Multiply the fractions:** $$\frac{21 \times 20}{2 \times 3} = \frac{420}{6} = 70$$ So, the area is 70 square yards. 5. **Calculate the total cost:** $$\text{Cost} = \text{Area} \times \text{Cost per square yard} = 70 \times 8 = 560$$ 6. **Final answer:** The total cost to resod the lawn is 560.