1. The problem states that Layla makes one basket out of every three shots she attempts, represented by the equation $m = \frac{1}{3}a$, where $m$ is the number of shots made and $a$ is the number of attempts. 2. To complete the table, use the formula $m = \frac{1}{3}a$ for each attempt value to find the shots made. 3. For $a=12$, $m = \frac{1}{3} \times 12 = 4$. 4. For $a=15$, $m = \frac{1}{3} \times 15 = 5$. 5. For $m=8$, find $a$ by rearranging the formula: $a = \frac{m}{\frac{1}{3}} = 8 \times 3 = 24$. 6. For $a=33$, $m = \frac{1}{3} \times 33 = 11$. 7. For $a=36$, $m = \frac{1}{3} \times 36 = 12$. 8. For $m=\text{typ}$ in the second row corresponding to $a=\text{typ}$ in the first row, the missing values are $a=24$ and $m=8$ as found. Final completed table: | Layla's Attempts | 12 | 15 | 24 | 33 | 36 | | Shots Layla Makes | 4 | 5 | 8 | 11 | 12 |