1. **Stating the problem:** We are given two tables, Table 1 and Table 2, each containing matrices with elements labeled as $[L_i, L_j, L_k]$. We need to calculate the LCIFEWA operator defined as: $$L \left[ \left( \prod \frac{x \times 2}{x} \right)^x \cdot \left( \prod \frac{x \times 2}{x} \right)^x \cdot \left( \prod \frac{x \times 2}{x} \right)^x \right]$$ using the data from Table 1 and Table 2. 2. **Understanding the formula:** The formula involves a product notation $\prod$ of the expression $\frac{x \times 2}{x}$ raised to the power $x$, repeated three times and multiplied together inside the operator $L[\cdot]$. 3. **Simplifying the product inside the formula:** Note that: $$\frac{x \times 2}{x} = 2$$ Since $x \neq 0$, the $x$ cancels out. 4. **Evaluating the product $\prod 2$:** The product $\prod 2$ over any index set of size $n$ is simply $2^n$. 5. **Determining the size of the product index $n$:** From the tables, each has 3 rows and 4 columns, so total elements per table is $3 \times 4 = 12$. Assuming the product runs over these 12 elements, then: $$\prod \frac{x \times 2}{x} = 2^{12}$$ 6. **Raising the product to the power $x$:** $$\left( 2^{12} \right)^x = 2^{12x}$$ 7. **Calculating the entire expression inside $L[\cdot]$:** The expression is the product of three identical terms: $$2^{12x} \cdot 2^{12x} \cdot 2^{12x} = 2^{12x + 12x + 12x} = 2^{36x}$$ 8. **Final expression:** $$L \left[ 2^{36x} \right]$$ 9. **Interpretation:** The LCIFEWA operator $L$ acts on the scalar $2^{36x}$. Without additional definition of $L$, the result is expressed as above. --- **Summary:** Using the data size from Table 1 and Table 2, the product inside the LCIFEWA operator simplifies to $2^{36x}$. Thus, $$\boxed{L \left[ 2^{36x} \right]}$$ is the simplified form of the LCIFEWA operator applied to the given formula. This step-by-step solution can be used in your thesis to explain the calculation clearly.