1. **State the problem:** We have two ratio tables showing the relationship between time (in minutes) and liters leaked for a Water Tank and a Swimming Pool. We need to complete the missing values in the tables and analyze the relationship.
2. **Water Tank table completion:** Given:
- At 2 min, 4 liters leaked.
Assuming the leak rate is constant, the ratio of liters leaked to time is constant.
Formula: $$\text{Rate} = \frac{\text{Liters Leaked}}{\text{Time}}$$
Calculate rate:
$$\frac{4}{2} = 2 \text{ liters per minute}$$
Use this rate to find missing values:
- At 4 min: $$4 \times 2 = 8$$ liters
- At 6 min: $$6 \times 2 = 12$$ liters
- At 8 min: $$8 \times 2 = 16$$ liters
3. **Swimming Pool table completion:** Given:
- At 3 min, 2 liters leaked.
Calculate rate:
$$\frac{2}{3} \approx 0.6667 \text{ liters per minute}$$
Use this rate to find missing values:
- At 6 min: $$6 \times 0.6667 = 4$$ liters
- At 9 min: $$9 \times 0.6667 = 6$$ liters
- At 12 min: $$12 \times 0.6667 = 8$$ liters
4. **Conclusion:** Both tables show a constant rate of leakage, but the Water Tank leaks faster (2 liters/min) than the Swimming Pool (2/3 liters/min). The relationship between time and liters leaked is proportional in both cases.
Final completed tables:
Water Tank:
| Time (min) | Liters Leaked |
|------------|---------------|
| 2 | 4 |
| 4 | 8 |
| 6 | 12 |
| 8 | 16 |
Swimming Pool:
| Time (min) | Liters Leaked |
|------------|---------------|
| 3 | 2 |
| 6 | 4 |
| 9 | 6 |
| 12 | 8 |
Leakage Rates 43Ef98
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