Subjects algebra

Length Difference 3Daad1

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1. **State the problem:** Find how much longer the length of the rectangular garden is than the width. 2. **Given:** Length = $3x^2 + 4x + 1$ Width = $x^2 - 12$ 3. **Formula:** Difference = Length - Width 4. **Calculate the difference:** $$ (3x^2 + 4x + 1) - (x^2 - 12) = 3x^2 + 4x + 1 - x^2 + 12 $$ 5. **Simplify:** $$ (3x^2 - x^2) + 4x + (1 + 12) = 2x^2 + 4x + 13 $$ 6. **Answer:** The length is $2x^2 + 4x + 13$ longer than the width. --- 1. **State the problem:** Find the expression for the area of Mia's square backyard. 2. **Given:** Side length = $n - 7$ 3. **Formula:** Area of square = side$^2$ 4. **Calculate the area:** $$ (n - 7)^2 = (n - 7)(n - 7) $$ 5. **Expand:** $$ n^2 - 7n - 7n + 49 = n^2 - 14n + 49 $$ 6. **Answer:** The area expression is $n^2 - 14n + 49$.