1. The problem states that in a code, CAT = DBU. 2. We need to find the code for DOG based on the same pattern. 3. Let's analyze the transformation from CAT to DBU letter by letter: - C to D: C is the 3rd letter, D is the 4th letter, so +1 shift. - A to B: A is the 1st letter, B is the 2nd letter, so +1 shift. - T to U: T is the 20th letter, U is the 21st letter, so +1 shift. 4. The pattern is each letter is shifted forward by 1 in the alphabet. 5. Apply the same shift to DOG: - D (4th letter) + 1 = E (5th letter) - O (15th letter) + 1 = P (16th letter) - G (7th letter) + 1 = H (8th letter) 6. Therefore, DOG in the code is EPH.