1. **Problem Statement:** Identify the slope and y-intercept of the line passing through points approximately $(-3,-2)$ and $(2,2)$. 2. **Formula for slope:** The slope $m$ of a line through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by $$m=\frac{y_2 - y_1}{x_2 - x_1}$$ 3. **Calculate slope for the first line:** $$m=\frac{2 - (-2)}{2 - (-3)}=\frac{2 + 2}{2 + 3}=\frac{4}{5}$$ 4. **Find y-intercept:** Use the slope-intercept form $y=mx+b$. Substitute one point, say $(2,2)$: $$2=\frac{4}{5} \times 2 + b$$ $$2=\frac{8}{5} + b$$ $$b=2 - \frac{8}{5}=\frac{10}{5} - \frac{8}{5}=\frac{2}{5}$$ 5. **Answer for first line:** Slope $m=\frac{4}{5}$, y-intercept $b=\frac{2}{5}$. The first line equation is $$y=\frac{4}{5}x + \frac{2}{5}$$