1. The problem is to analyze the line given by the equation $5x + 4y = 8$ and understand its graph. 2. The standard form of a line is $Ax + By = C$. Here, $A=5$, $B=4$, and $C=8$. 3. To find the intercepts, set $x=0$ to find the $y$-intercept and set $y=0$ to find the $x$-intercept. 4. For the $y$-intercept, set $x=0$: $$5(0) + 4y = 8 \Rightarrow 4y = 8 \Rightarrow y = \frac{8}{4} = 2$$ 5. For the $x$-intercept, set $y=0$: $$5x + 4(0) = 8 \Rightarrow 5x = 8 \Rightarrow x = \frac{8}{5} = 1.6$$ 6. The slope-intercept form is $y = mx + b$. Solve for $y$: $$5x + 4y = 8 \Rightarrow 4y = 8 - 5x \Rightarrow y = \frac{8 - 5x}{4} = 2 - \frac{5}{4}x$$ 7. The slope $m$ is $-\frac{5}{4}$ and the $y$-intercept $b$ is $2$. 8. The line crosses the $y$-axis at $(0,2)$ and the $x$-axis at $(1.6,0)$. 9. The graph is a straight line descending from left to right because the slope is negative. 10. The point $Q(0,5)$ is above the line since substituting $x=0$ gives $y=2$ on the line, and $5 > 2$. Final answer: The line $5x + 4y = 8$ has slope $-\frac{5}{4}$, $y$-intercept $(0,2)$, $x$-intercept $(1.6,0)$, and the point $Q(0,5)$ lies above it.