1. **State the problem:** We need to find the equation of line B, which passes through point P(2, 5) and is parallel to line A. 2. **Find the slope of line A:** Line A passes through points (2, 1) and (5, 7). Calculate the slope $m$ using the formula: $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{7 - 1}{5 - 2} = \frac{6}{3} = 2$$ 3. **Since line B is parallel to line A, it has the same slope:** $$m_B = 2$$ 4. **Use the point-slope form to find the equation of line B:** Point-slope form is: $$y - y_1 = m(x - x_1)$$ Using point P(2, 5): $$y - 5 = 2(x - 2)$$ 5. **Simplify to slope-intercept form $y = mx + c$:** $$y - 5 = 2x - 4$$ $$y = 2x - 4 + 5$$ $$y = 2x + 1$$ **Final answer:** $$y = 2x + 1$$