Subjects algebra

Line Bisector 20A98C

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1. **State the problem:** We are given that line \(\ell\) bisects segment \(KP\) at point \(L\). This means \(L\) is the midpoint of \(KP\), so \(KL = LP\). 2. **Given expressions:** \(KL = 7x + 1\) \(LP = 8x - 3\) 3. **Set up the equation using the midpoint property:** Since \(L\) bisects \(KP\), $$7x + 1 = 8x - 3$$ 4. **Solve for \(x\):** $$7x + 1 = 8x - 3$$ Subtract \(7x\) from both sides: $$\cancel{7x} + 1 = \cancel{7x} + 8x - 3 \Rightarrow 1 = x - 3$$ Add 3 to both sides: $$1 + 3 = x - 3 + 3 \Rightarrow 4 = x$$ 5. **Find \(KL\) by substituting \(x=4\):** $$KL = 7(4) + 1 = 28 + 1 = 29$$ 6. **Since \(KL = LP\), find \(LP\):** $$LP = 8(4) - 3 = 32 - 3 = 29$$ 7. **Find \(KP\) by adding \(KL + LP\):** $$KP = KL + LP = 29 + 29 = 58$$ **Final answer:** $$\boxed{58}$$