1. **State the problem:** We need to determine the equation of the line passing through the points (-12, -12) and (8, 8). 2. **Recall the formula for the equation of a line:** The slope-intercept form is $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Calculate the slope $m$:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{8 - (-12)}{8 - (-12)} = \frac{8 + 12}{8 + 12} = \frac{20}{20} = 1$$ 4. **Use the slope and one point to find $b$:** Using point (-12, -12), substitute into $y = mx + b$: $$-12 = 1 \times (-12) + b$$ $$-12 = -12 + b$$ $$b = -12 + 12 = 0$$ 5. **Write the final equation:** $$y = 1x + 0$$ or simply $$y = x$$ This matches the line shown in the graph, confirming the equation is $y = x$.