Subjects algebra

Line Equation 11Df31

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1. The problem asks for the slope-intercept form equation of the line passing through the point (4, -3) with slope $m = -2$. 2. Recall the slope-intercept form of a line is given by: $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. We know $m = -2$ and the line passes through $(x_1, y_1) = (4, -3)$. 4. Substitute these values into the equation to find $b$: $$-3 = -2 \times 4 + b$$ $$-3 = -8 + b$$ 5. Solve for $b$: $$b = -3 + 8$$ $$b = 5$$ 6. Therefore, the slope-intercept form equation is: $$y = -2x + 5$$ Final answer: $y = -2x + 5$