1. **State the problem:** We need to find the equation of a line that passes through the point $(3, -8)$ and has a slope of $-3$. The equation should be in standard form, which is $Ax + By = C$ where $A$, $B$, and $C$ are integers. 2. **Recall the point-slope form:** The point-slope form of a line is given by: $$y - y_1 = m(x - x_1)$$ where $m$ is the slope and $(x_1, y_1)$ is a point on the line. 3. **Substitute the given point and slope:** $$y - (-8) = -3(x - 3)$$ which simplifies to $$y + 8 = -3x + 9$$ 4. **Isolate $y$ to write in slope-intercept form:** $$y = -3x + 9 - 8$$ $$y = -3x + 1$$ 5. **Convert to standard form:** Move all terms to one side: $$3x + y = 1$$ 6. **Check the options:** The equation $3x + y = 1$ matches one of the given options. **Final answer:** The equation of the line in standard form is: $$3x + y = 1$$