1. **State the problem:** Find the equation of the straight line passing through points $(0,2)$ and $(9,-1)$ in the form $ax + by = c$ where $a$, $b$, and $c$ are integers in lowest terms. 2. **Find the slope $m$ of the line:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 - 2}{9 - 0} = \frac{-3}{9} = -\frac{1}{3}$$ 3. **Use point-slope form:** Using point $(0,2)$, $$y - 2 = -\frac{1}{3}(x - 0)$$ $$y - 2 = -\frac{1}{3}x$$ 4. **Rewrite in standard form $ax + by = c$:** Multiply both sides by 3 to clear the fraction: $$3(y - 2) = 3\left(-\frac{1}{3}x\right)$$ $$3y - 6 = -x$$ Rewrite: $$x + 3y = 6$$ 5. **Check coefficients:** $a=1$, $b=3$, $c=6$ are integers and in lowest terms. **Final answer:** $$x + 3y = 6$$