1. The problem asks us to find the equation of a line in slope-intercept form given the slope and a point on the line. 2. The slope-intercept form of a line is given by the formula: $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. We are given the slope $m = -1$ and a point $(-16, 13)$ that lies on the line. 4. Substitute the slope and the coordinates of the point into the equation to solve for $b$: $$13 = (-1)(-16) + b$$ 5. Simplify the right side: $$13 = 16 + b$$ 6. Solve for $b$ by subtracting 16 from both sides: $$b = 13 - 16 = -3$$ 7. Now that we have $b = -3$, write the equation of the line: $$y = -1x - 3$$ 8. Simplify the equation: $$y = -x - 3$$ Final answer: $$y = -x - 3$$