1. **State the problem:** Find the equation of the straight line passing through points (-5, 0) and (0, 5) in the form $y = mx + c$. 2. **Formula used:** The equation of a line is $y = mx + c$, where $m$ is the slope and $c$ is the y-intercept. 3. **Calculate the slope $m$:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - 0}{0 - (-5)} = \frac{5}{5} = 1$$ 4. **Find the y-intercept $c$:** The line crosses the y-axis at $y=5$, so $c = 5$. 5. **Write the equation:** $$y = 1 \cdot x + 5$$ 6. **Final answer:** $$y = x + 5$$