1. **State the problem:**
We are given a graph with points (0,3), (1,1), and (3,-3). We need to find:
a) The y-intercept of the graph.
b) The equation of the line in slope-intercept form.
2. **Find the y-intercept:**
The y-intercept is the point where the line crosses the y-axis, which occurs when $x=0$.
From the point (0,3), the y-intercept is $3$.
3. **Find the slope:**
The slope formula is:
$$m = \frac{y_2 - y_1}{x_2 - x_1}$$
Using points (0,3) and (1,1):
$$m = \frac{1 - 3}{1 - 0} = \frac{-2}{1} = -2$$
4. **Write the equation in slope-intercept form:**
The slope-intercept form is:
$$y = mx + b$$
where $m$ is the slope and $b$ is the y-intercept.
Substitute $m = -2$ and $b = 3$:
$$y = -2x + 3$$
**Final answers:**
a) The y-intercept is $3$.
b) The equation of the line is $y = -2x + 3$.
Line Equation 2Fa16F
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.