Subjects algebra

Line Equation 2Fa16F

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1. **State the problem:** We are given a graph with points (0,3), (1,1), and (3,-3). We need to find: a) The y-intercept of the graph. b) The equation of the line in slope-intercept form. 2. **Find the y-intercept:** The y-intercept is the point where the line crosses the y-axis, which occurs when $x=0$. From the point (0,3), the y-intercept is $3$. 3. **Find the slope:** The slope formula is: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ Using points (0,3) and (1,1): $$m = \frac{1 - 3}{1 - 0} = \frac{-2}{1} = -2$$ 4. **Write the equation in slope-intercept form:** The slope-intercept form is: $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. Substitute $m = -2$ and $b = 3$: $$y = -2x + 3$$ **Final answers:** a) The y-intercept is $3$. b) The equation of the line is $y = -2x + 3$.