1. **State the problem:** Find the equation of the straight line $L$ in the form $y = mx + c$ given two points on the line: $(0, 2)$ and $(3, 0)$. 2. **Recall the formula:** The equation of a line is $y = mx + c$, where $m$ is the slope and $c$ is the y-intercept. 3. **Calculate the slope $m$:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 2}{3 - 0} = \frac{-2}{3}$$ 4. **Identify the y-intercept $c$:** Since the line passes through $(0, 2)$, the y-intercept is $c = 2$. 5. **Write the equation:** Substitute $m$ and $c$ into $y = mx + c$: $$y = -\frac{2}{3}x + 2$$ 6. **Interpretation:** The line decreases as $x$ increases, crossing the y-axis at 2 and the x-axis at 3. **Final answer:** $$y = -\frac{2}{3}x + 2$$