1. **State the problem:** Find the equation of the line passing through the points (10, 9) and (5, 12) in slope-intercept form $y = mx + b$. 2. **Find the slope $m$ using the slope formula:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{12 - 9}{5 - 10} = \frac{3}{-5} = -\frac{3}{5}$$ 3. **Use the slope and one point to find $b$:** Using point (10, 9), substitute into $y = mx + b$: $$9 = -\frac{3}{5} \times 10 + b$$ $$9 = -\frac{30}{5} + b$$ $$9 = -6 + b$$ Add 6 to both sides: $$9 + 6 = b$$ $$b = 15$$ 4. **Write the equation in slope-intercept form:** $$y = -\frac{3}{5}x + 15$$ **Final answers:** - Slope $m = -\frac{3}{5}$ - Intercept $b = 15$ - Equation: $y = -\frac{3}{5}x + 15$