1. The problem is to find the equation of the line passing through the points (-8, -7) and (8, 7). 2. The formula for the slope $m$ of a line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$ is: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 3. Substitute the given points into the slope formula: $$m = \frac{7 - (-7)}{8 - (-8)} = \frac{7 + 7}{8 + 8} = \frac{14}{16}$$ 4. Simplify the fraction by canceling common factors: $$m = \frac{\cancel{14}^{7} \times 2}{\cancel{16}^{8} \times 2} = \frac{7}{8}$$ 5. Use the point-slope form of the line equation: $$y - y_1 = m(x - x_1)$$ 6. Substitute $m = \frac{7}{8}$ and point $(-8, -7)$: $$y - (-7) = \frac{7}{8}(x - (-8))$$ $$y + 7 = \frac{7}{8}(x + 8)$$ 7. Distribute the slope on the right side: $$y + 7 = \frac{7}{8}x + \frac{7}{8} \times 8$$ $$y + 7 = \frac{7}{8}x + 7$$ 8. Subtract 7 from both sides: $$y + 7 - 7 = \frac{7}{8}x + 7 - 7$$ $$y = \frac{7}{8}x$$ 9. The equation of the line is: $$y = \frac{7}{8}x$$ 10. Check the points to confirm correctness: For $x = -8$, $$y = \frac{7}{8} \times (-8) = -7$$ For $x = 8$, $$y = \frac{7}{8} \times 8 = 7$$ This matches the given points, so the equation is correct.