1. **State the problem:** Find the equation of the line passing through points approximately (-1,12) and (1,-12) in slope-intercept form $y=mx+b$. 2. **Formula:** The slope $m$ of a line through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$m=\frac{y_2-y_1}{x_2-x_1}$$ The slope-intercept form is: $$y=mx+b$$ where $b$ is the y-intercept. 3. **Calculate the slope:** $$m=\frac{-12-12}{1-(-1)}=\frac{-24}{2}=-12$$ 4. **Find the y-intercept $b$:** Use point $(-1,12)$: $$12=(-12)(-1)+b$$ $$12=12+b$$ $$\cancel{12}=\cancel{12}+b$$ $$b=0$$ 5. **Write the equation:** $$y=-12x+0$$ or simply $$y=-12x$$ **Final answer:** The equation of the line in slope-intercept form is $y=-12x$.