1. **State the problem:** Given the table of points, find the equation of the line that passes through these points and describe its graph. 2. **Identify the points:** The points given are $(-3, -10)$, $(-2, -6)$, $(-1, -2)$, $(0, 2)$, $(1, 6)$, and $(2, 10)$. 3. **Find the slope $m$ of the line:** The slope formula is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ Using points $(-3, -10)$ and $(-2, -6)$: $$m = \frac{-6 - (-10)}{-2 - (-3)} = \frac{-6 + 10}{-2 + 3} = \frac{4}{1} = 4$$ 4. **Find the y-intercept $b$:** Use the slope-intercept form $y = mx + b$ and substitute one point, for example $(0, 2)$: $$2 = 4 \times 0 + b \implies b = 2$$ 5. **Write the equation of the line:** $$y = 4x + 2$$ 6. **Verify with another point:** Check $(1, 6)$: $$y = 4(1) + 2 = 4 + 2 = 6$$ which matches the table. 7. **Interpretation:** The line has slope 4, meaning for every increase of 1 in $x$, $y$ increases by 4. The line crosses the y-axis at 2. **Final answer:** $$y = 4x + 2$$