1. **State the problem:** Find the equation of the line passing through the point $(-3,0)$ with slope $\frac{2}{3}$. 2. **Formula used:** The point-slope form of a line is given by: $$y - y_1 = m(x - x_1)$$ where $m$ is the slope and $(x_1, y_1)$ is a point on the line. 3. **Substitute the given values:** $$y - 0 = \frac{2}{3}(x - (-3))$$ which simplifies to $$y = \frac{2}{3}(x + 3)$$ 4. **Distribute the slope:** $$y = \frac{2}{3}x + \frac{2}{3} \times 3$$ $$y = \frac{2}{3}x + 2$$ 5. **Final equation:** The equation of the line is $$y = \frac{2}{3}x + 2$$ This means for every increase of 3 units in $x$, $y$ increases by 2 units, and the line crosses the $y$-axis at 2.