1. **State the problem:** We need to find the equation of a line in slope-intercept form $y=mx+b$ that passes through the point $(-3,5)$ and has slope $m=-2$. 2. **Recall the slope-intercept form:** The equation of a line is given by $$y=mx+b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Substitute the known slope:** We know $m=-2$, so the equation becomes $$y=-2x+b$$ 4. **Use the point to find $b$:** Substitute $x=-3$ and $y=5$ into the equation: $$5 = -2(-3) + b$$ $$5 = 6 + b$$ 5. **Solve for $b$:** $$b = 5 - 6$$ $$b = -1$$ 6. **Write the final equation:** Substitute $b=-1$ back into the equation: $$y = -2x - 1$$ **Answer:** The right side of the slope-intercept form is $-2x - 1$.