1. **State the problem:** Given the points $(-4,-4), (-2,-1), (0,2), (2,5), (4,8), (6,11)$, find the equation of the line passing through these points. 2. **Formula used:** The equation of a line in slope-intercept form is $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Calculate the slope $m$:** Use any two points, for example $(0,2)$ and $(2,5)$. $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - 2}{2 - 0} = \frac{3}{2}$$ 4. **Find the y-intercept $b$:** Substitute $m=\frac{3}{2}$ and point $(0,2)$ into $y = mx + b$. $$2 = \frac{3}{2} \times 0 + b \implies b = 2$$ 5. **Write the equation:** $$y = \frac{3}{2}x + 2$$ 6. **Verify with another point:** Check $(4,8)$. $$y = \frac{3}{2} \times 4 + 2 = 6 + 2 = 8$$ which matches the point. **Final answer:** $$y = \frac{3}{2}x + 2$$