1. **State the problem:** We need to find the equation of a line in slope-intercept form, which is $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 2. **Identify given points:** The line crosses the y-axis at $y=3$, so the y-intercept is $b=3$. The line passes through the point $(6,0)$. 3. **Calculate the slope $m$:** The slope formula is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ Using points $(0,3)$ and $(6,0)$: $$m = \frac{0 - 3}{6 - 0} = \frac{-3}{6}$$ 4. **Simplify the slope:** $$m = \frac{\cancel{-3}}{\cancel{6}} = -\frac{1}{2}$$ 5. **Write the equation:** Substitute $m = -\frac{1}{2}$ and $b=3$ into slope-intercept form: $$y = -\frac{1}{2}x + 3$$ **Final answer:** $$y = -\frac{1}{2}x + 3$$