Subjects algebra

Line Equation 9Bfdea

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1. **State the problem:** We need to find the equation of the line passing through the points given in the table in slope-intercept form, which is $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 2. **Find the slope $m$:** The slope formula is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$. Using points $(1, -1)$ and $(-1, 1)$: $$m = \frac{-1 - 1}{1 - (-1)} = \frac{-2}{2} = -1$$ 3. **Find the y-intercept $b$:** Use the slope and one point in the equation $y = mx + b$ to solve for $b$. Using point $(1, -1)$: $$-1 = (-1)(1) + b$$ $$-1 = -1 + b$$ Add 1 to both sides: $$-1 + 1 = -1 + b + 1$$ $$0 = b$$ 4. **Write the equation:** Substitute $m = -1$ and $b = 0$ into the slope-intercept form: $$y = -1x + 0$$ Or simply: $$y = -x$$ **Final answer:** The equation of the line in slope-intercept form is $$y = -x$$.