1. **Problem:** Find the equation of the line passing through points (-1,7) and (2,-6). 2. **Formula:** The slope $m$ of a line through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$m=\frac{y_2-y_1}{x_2-x_1}$$ The equation of the line in point-slope form is: $$y - y_1 = m(x - x_1)$$ 3. **Calculate slope:** $$m=\frac{-6 - 7}{2 - (-1)}=\frac{-13}{3}$$ 4. **Write equation using point (-1,7):** $$y - 7 = -\frac{13}{3}(x + 1)$$ 5. **Simplify:** $$y - 7 = -\frac{13}{3}x - \frac{13}{3}$$ $$y = -\frac{13}{3}x - \frac{13}{3} + 7$$ $$y = -\frac{13}{3}x - \frac{13}{3} + \frac{21}{3}$$ $$y = -\frac{13}{3}x + \frac{8}{3}$$ **Final equation:** $$y = -\frac{13}{3}x + \frac{8}{3}$$ This line has a descending slope as expected.